X^2+10x+28=3

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Solution for X^2+10x+28=3 equation: 



X^2+10X+28=3

We move all terms to the left:

X^2+10X+28-(3)=0

We add all the numbers together, and all the variables

X^2+10X+25=0

a = 1; b = 10; c = +25;
Δ = b2-4ac
Δ = 102-4·1·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{-10}{2}=-5$

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